% for i in {1..10} do perl -le 'print for 2001..2010' > $i.log done % ls 1.log 10.log 2.log 3.log 4.log 5.log 6.log 7.log 8.log 9.log % cat 1.log 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 % perl -i.org -ple 's/^.{2}//' *.log % ls 1…